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Grade 11 / High 2 (age 16-17)

Sum of Series

Sum of Series

The sigma symbol Σ is shorthand for adding many terms together, one by one. When you add 1 to n, sums like the naturals or the squares appear so often that a short formula gives the answer at once. Once you see where these formulas come from, any messy series breaks into sums of k, k², and k³. Here a bar chart and a triangle of dots let you watch the sums build and see why the formula holds.

Meaning of the Sigma (Σ) Notation
5
💡 Σ means 'add them all up'
①Σ(k=1 to n) a_k = a₁ + a₂ + ... + a_n
②Bottom: start, top: end, right: rule
③Sum of bar heights = the value of Σ
Sum of Naturals — Triangular Numbers
5
Sum of Naturals
n(n+1)2
1 + 2 + 3 + ... + n = n(n+1)/2
Three Key Formulas
Σk
n(n+1)2
1 + 2 + ... + n
Σk²
n(n+1)(2n+1)6
1² + 2² + ... + n²
Σk³
[n(n+1)2]² = (Σk)²
1³ + 2³ + ... + n³ = (1+2+...+n)²
🔗 Surprising Identity
①Σk³ = (Σk)² — sum of cubes is the square of the sum!
②These three handle most sum problems
③Decompose any expression into k, k², k³
Properties of Σ
Linearity
Σ(cak + bk) = c·Σak + Σbk
Constants pull out, sums split
Recovering a_n
an = Sn - Sn-1 (n ≥ 2)
Get the general term back from the partial sum
⚠️ Watch Out
①n ≥ 2: a_n = S_n − S_{n-1}
②n = 1: a₁ = S₁ (check separately!)
③Verify the two agree
Wrap-up
Three Sum Formulas
Σk = n(n+1)2, Σk² = n(n+1)(2n+1)6, Σk³ = [n(n+1)2
Sums of naturals, squares, cubes
🎯 Exam Points
①Σk = n(n+1)/2 — basic
②Σk² = n(n+1)(2n+1)/6
③Σk³ = [n(n+1)/2]² = (Σk)²
④Σ is linear: pull out constants, split sums
⑤a_n = S_n − S_{n-1} (n ≥ 2); check a₁ = S₁ separately
Worked Examples & Past Exam
Example 1
Find the value of 1 + 2 + 3 + ... + 10.
1
Substitute n = 10 into the sum formula Σk = n(n+1)/2.
Σk = 10 × 112
2
Compute.
= 1102 = 55
55
The sum of the first n natural numbers is n(n+1)/2.
Example 2
Find the value of 1² + 2² + 3² + 4².
1
Substitute n = 4 into the sum formula Σk² = n(n+1)(2n+1)/6.
Σk² = 4 × 5 × 96
2
Compute.
= 1806 = 30
30
The sum of squares is n(n+1)(2n+1)/6.
2023 CSAT Math type, adapted
Express Σ(k=1 to n) (2k + 1) as an expression in n.
n(n+2)
n(n+1)
2n+1
n²+1
① n(n+2)
1
Split using linearity: Σ(2k+1) = 2Σk + Σ1.
Σ(2k+1) = 2 × n(n+1)2 + n
2
Simplify.
= n(n+1) + n = n² + 2n = n(n+2)
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