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Grade 10-11 (age 15-17)

high school physics Conservation of Mechanical Energy

A roller coaster speeds up as it comes down from a height because potential energy is turning into kinetic energy. Without friction or air resistance their sum, the mechanical energy, stays exactly as it started, so the height alone gives the speed at the bottom. The potential energy held at the top passes bit by bit into kinetic energy on the way down, and at the bottom all of it is kinetic. Move the height slider and the bars for the two energies trade places at the top, middle and bottom, while their sum always stays the same.

Energy Changing Form

🎢 The secret of the roller coaster
①A roller coaster goes faster the further it comes down
②Potential energy from height turns into kinetic energy from speed
③Without friction, the sum of the two energies is always the same
④The figure uses mass m = 1 kg and g = 9.8 m/s²
⑤With friction, part of the mechanical energy becomes heat

Conservation of Energy

5 m
💡 What to notice
①At the top all the energy is potential and the kinetic energy is 0
②In the middle, at half the height, the two energies are half each
③At the bottom the potential energy is 0 and all of it is kinetic
④Everywhere, potential energy + kinetic energy is the same

Energy Formulas

Kinetic energy
Ek = 12mv²
The energy of a moving object
Gravitational potential energy
Ep = mgh
The energy of an object at height h above the reference level
Conservation of mechanical energy
12mv₁² + mgh₁ = 12mv₂² + mgh₂
Without friction, the mechanical energy is the same at every position

Applying It to Free Fall

Speed at the bottom after falling from height h
v = √(2gh)
In mgh = ½mv² the mass m cancels from both sides, giving v = √(2gh)
⚡ The mass cancels
①Both sides of mgh = ½mv² contain m, so it cancels
②So, ignoring air resistance, a heavy ball and a light ball dropped from the same height land at the same speed
③This is the idea behind Galileo's famous Leaning Tower of Pisa story
④A pendulum works the same way: fastest at the lowest point and momentarily at rest at the highest

Worked Examples

Example 1
An object is released from rest at a height of 20 m and falls freely. How fast is it moving as it reaches the ground? Use g = 10 m/s².
1
In mgh = ½mv² the mass cancels, so v = √(2gh).
v = √(2gh)
2
Put in g = 10 and h = 20.
v = √(2 × 10 × 20) = √400 = 20 m/s
▸ 20 m/s
The speed at the bottom, √(2gh), does not depend on the mass.
Example 2
An object is released from rest at a height of 5 m. At what height are its kinetic and potential energies equal?
1
The starting energy is the potential energy at the top, mg × 5. When kinetic and potential energy are equal, each is half of that.
Ep = 12Etotal = 12mg(5)
2
Solve mgh = ½ × mg × 5 for h.
mgh = 12mg × 5 ⇒ h = 2.5 m
▸ 2.5 m
The two energies are equal at half the starting height every time, whatever the mass and g.

Summary

Kinetic energy
Ek = 12mv²
Potential energy
Ep = mgh
Conservation of energy
Ek + Ep = const (no friction)
The kinetic energy gains exactly what the potential energy loses
CSAT-style problem, adapted
An object is released from rest on a frictionless slope and reaches 6 m/s at the bottom. What was its starting height? Use g = 10 m/s².
①1.2 m
②1.5 m
③1.8 m
④2.4 m
⑤3.6 m
▸ ③ 1.8 m
1
There is no friction, so mgh = ½mv², giving h = v²/(2g).
mgh = 12mv2 ⇒ h = v22g
2
Put in v = 6 and g = 10.
h = 622 × 10 = 3620 = 1.8 m
🎯 Exam Points
①Mechanical energy = kinetic energy + potential energy
②It is conserved when there is no friction or air resistance
③The speed after falling from height h is v = √(2gh), whatever the mass
④A pendulum is fastest at its lowest point and stops at its highest
⑤With friction, the mechanical energy drops by the work done by friction, which becomes heat

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