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Grade 11-12 (age 16-18)

Conditional Probability

Conditional Probability

Once you learn that something has already happened, the probability of the very same event can change. Conditional probability shrinks the sample space down to B and looks at A again under that condition, and from there the multiplication rule and Bayes' theorem follow naturally. Bayes in particular lets you reason backward from an effect to its cause, explaining why a positive test can still mean a low real chance when the disease is rare. Drag the P(A), P(B), and P(A∩B) sliders to see how P(A|B) shifts, then use the prevalence slider to uncover what a positive result truly means.

Conditions Change Probability
🔍 What is Conditional Probability?
①Probability of A given B has occurred
②Sample space shrinks from S to B
③Putting on B-tinted glasses to look at A again
Visualize P(A|B)
4
5
2
Definition
P(A|B) = P(A ∩ B)P(B)
Probability of A given B (with P(B) > 0)
Multiplication Rule
P(A ∩ B) = P(B) × P(A|B) = P(A) × P(B|A)
Probability that both occur
Bayes Theorem
1%
🏥 Medical Test Paradox
①With 1% prevalence, a positive may still mean low actual probability of disease
②Positive test → truly sick? That is Bayes
③Low prior → low posterior
Bayes
P(A|B) = P(B|A) × P(A)P(B)
Infer cause probability from observed effect
Work It Out
Example 1
If P(A) = 1/2 and P(A∩B) = 1/3, find the conditional probability P(B|A).
1
Write the definition of conditional probability.
P(B|A) = P(A∩B)/P(A)
2
Substitute.
= (1/3)/(1/2) = 2/3
2/3
Conditional probability is the probability of B given that A has occurred.
Example 2
In a class of 30, 18 wear glasses and 12 of those are boys. Picking one glasses-wearer, find the probability of a boy.
1
Restrict the sample space to the condition (the 18 glasses-wearers).
P(boy | glasses) = (boys with glasses)/(glasses-wearers)
2
Substitute.
= 12/18 = 2/3
2/3
Conditional probability narrows the sample space to the given condition.
Wrap-up
Core
P(A|B) = P(A ∩ B)P(B), P(A|B) = P(B|A)P(A)P(B)
Conditional probability + Bayes
Education-office assessment type
For events A, B with P(A) = 0.4 and P(B|A) = 0.5, find P(A∩B).
0.1
0.2
0.3
0.4
0.5
② 0.2
1
Use the multiplication rule of probability.
P(A∩B) = P(A) × P(B|A)
2
Substitute.
= 0.4 × 0.5 = 0.2
🎯 Exam Points
①Conditional: P(A|B) = P(A∩B)/P(B)
②Multiplication: P(A∩B) = P(B)·P(A|B)
③Independent ⇒ P(A|B) = P(A)
④Bayes: outcome → cause inference
⑤Tree diagrams decompose total probability
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Meaning of Probability
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Independent Trials
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