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Grade 11-12 (age 16-18)

high school Indefinite Integral

An indefinite integral runs differentiation backwards: it looks for the original function whose derivative is the given one. A constant becomes 0 when differentiated and vanishes, so there is not one such function but endlessly many, each differing by a constant. That is why the result of an indefinite integral always carries a constant of integration C to fill the place of the lost constant. In the first picture, changing C moves the curve x² + C up or down without changing its shape, and the tangent slope at x = 1 is 2 on every curve.

Integration undoes differentiation

🔄 The idea of the indefinite integral
①Find a function F(x) whose derivative is f(x)
②Such an F(x), with F'(x) = f(x), is an indefinite integral of f(x)
③Adding any constant to F(x) leaves the derivative unchanged, so there are endlessly many answers

An indefinite integral is a family of curves

0
Definition of the indefinite integral
∫ f(x) dx = F(x) + C (where F'(x) = f(x))
It stands for all antiderivatives of f(x); C is the constant of integration
💡 What the constant C means
①C is fixed only when a condition such as a starting value is given
②For example, integrating the velocity v(t) = 2t gives the position s(t) = t² + C, with C = s(0)
③When finding an indefinite integral, never leave out + C

Differentiation and integration undo each other

2
Power Rule for Integration
∫ xn dx = xn+1n+1 + C (n ≠ -1)
The power rule (xⁿ)' = nxⁿ⁻¹ used backwards

Basic Integration Rules

Constant multiples, sums and differences
∫ kf(x) dx = k∫ f(x) dx, ∫ [f ± g] dx = ∫ f dx ± ∫ g dx
Constant multiples come out of the integral; sums and differences are integrated term by term
Constant
∫ k dx = kx + C
Linear
∫ x dx = x²/2 + C
Quadratic
∫ x² dx = x³/3 + C
Power n
∫ xn dx = xn+1n+1 + C (n ≠ -1)

Summary

Indefinite Core
∫ xn dx = xn+1n+1 + C (n ≠ -1)
Undo differentiation and add the constant C
🎯 Exam Points
①An indefinite integral undoes differentiation; always add + C
②Integrating xⁿ raises the exponent to n + 1 and puts 1/(n + 1) in front
③Integrate a polynomial term by term and add
④A condition such as a starting value fixes C
⑤Check: differentiating your answer should give back the original function

Worked Examples & Past Exam

Example 1
Find ∫ (3x² + 2x) dx.
1
Apply ∫ xⁿ dx = xⁿ⁺¹/(n + 1) to each term.
∫ 3x2 dx = x3, ∫ 2x dx = x2
2
Add the constant of integration C at the end.
∫ (3x2 + 2x) dx = x3 + x2 + C
▸ x³ + x² + C
Differentiating x³ + x² + C gives back 3x² + 2x, which confirms the answer.
Example 2
If F'(x) = 2x + 1 and F(0) = 3, find F(x).
1
Integrating 2x + 1 gives F(x) = x² + x + C.
F(x) = x2 + x + C
2
Use F(0) = 3 to fix C.
F(0) = C = 3 ⟹ F(x) = x2 + x + 3
▸ F(x) = x² + x + 3
This picks out, from the whole family of curves, the one that passes through (0, 3). One condition fixes one constant C.
2023 CSAT Math type, adapted
What is ∫ (6x² − 4x) dx? (C is the integration constant)
①2x³ − 2x² + C
②2x³ − 4x² + C
③6x³ − 4x² + C
④x³ − x² + C
⑤12x − 4 + C
▸ ① 2x³ − 2x² + C
1
Integrating term by term, 6x² becomes 2x³ and 4x becomes 2x².
∫ 6x2 dx = 2x3, ∫ 4x dx = 2x2
2
Keep the minus sign and add the constant C.
2x3 - 2x2 + C

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