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Grade 11 / High 2 (age 16-17)

Common Logarithm

Common Logarithm

Logarithm Base 10
200
👀 See It
①The common logarithm has base 10: log x = log_{10} x
②The common log of a positive number splits into an integer part (characteristic) and a fractional part in [0,1) (mantissa)
③Each time x grows tenfold, the log value increases by 1
Characteristic and Mantissa
Characteristic + mantissa
log N = (characteristic) + (mantissa), 0 ≤ mantissa < 1
The characteristic is an integer, the mantissa is in [0,1) — they hold the digit count and the digit pattern separately
Digit count and characteristic
integer N has d digits ⇔ characteristic = d − 1 ⇔ 10d-1 ≤ N < 10d
If the characteristic is d−1, then N is a d-digit integer
Equal Mantissas Mean Equal Digit Patterns
🔢 Shift by a Power of 10
①Two numbers with the same mantissa share the digit pattern and differ only by a power of 10
②e.g., log 2 and log 200 have the same mantissa
③The characteristic sets the decimal position (digit count); the mantissa sets the digits
Compute It Directly
Example 1
Given log 2 = 0.3010, find log 200.
1
Factor 200 = 2 × 100 = 2 × 10².
log 200 = log 2 + log 102
2
Add log 10² = 2.
= 0.3010 + 2 = 2.3010
2.3010 (char. 2, mant. 0.3010)
A power of 10 changes only the characteristic, leaving the mantissa (0.3010) intact.
Example 2
How many digits does 230 have? (log 2 = 0.3010)
1
Take the common logarithm.
log 230 = 30 log 2 = 30 × 0.3010 = 9.03
2
The characteristic is 9, so the digit count is 9 + 1.
char. 9 ⇒ 10 digits
10 digits
The digit count of a power comes straight from the log characteristic + 1.
Wrap-up
Key result
log N = char. + mant., d digits ⇔ char. = d − 1
Characteristic = digit count, mantissa = digit pattern — separating them is the key
2021 CSAT Math type, adapted
How many digits does 320 have? (log 3 = 0.4771)
9 digits
10 digits
11 digits
12 digits
13 digits
② 10 digits
1
Take the common logarithm to get the characteristic.
log 320 = 20 × 0.4771 = 9.542
2
The characteristic is 9, so digit count = 9 + 1.
char. 9 ⇒ 10 digits
🎯 Exam Points
①log N = char. + mant. (0 ≤ mant. < 1)
②d-digit integer ⇔ char. = d − 1
③digit count of a power = log characteristic + 1
④equal mantissas ⇒ same digit pattern
⑤if 0<N<1 the characteristic is negative (position of first nonzero decimal)
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