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Grade 10 / High 1 (age 15-16)

high school Polynomial Operations

Polynomial Operations

Multiplying and dividing polynomials extends the arithmetic you already know from numbers to letters. The product of two linear terms splits a rectangle into four pieces, while synthetic division gives the quotient and remainder fast. Just like 17 = 5 × 3 + 2, every polynomial follows f(x) = divisor × quotient + remainder. Drag the sliders for b and the constant term and the area model and the division table reshape.

Multiplying Polynomials — Area Model

If you memorize multiply and divide as separate tricks, a term that came from a tile has no seat in the division table. The area tiles and the coefficient table sit on one page so the same letter x keeps the same place in both drawings. The habit of writing quotient and remainder in separate seats, already used with integers, is the starting point when those seats become letters. Seeing where a term came from cuts later sign errors more than reciting a list of formulas.

A product of two polynomials is the area of a rectangle. Expanding (x + 3)(x + b) is the sum of four sub-rectangles. In this sketch a is fixed at 3.

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The product picture is one large square plus three tiles at the right, bottom, and corner. The large cell shows x²; the upper-right tile shows the slider value times x; the bottom tile shows 3x; the corner shows the product of 3 and the slider. Moving b from 1 to 7 redraws only the width of the two right-hand tiles, and the linear coefficient and constant at the bottom of the picture change with them. The synthetic table has 1 on the left and 1, 2, -5, then the constant slider on the top row; the last cell of the bottom row is drawn in gold as the remainder. Changing the constant from -5 to 10 changes that last cell and the remainder label; the three coefficients that drop down stay.

💡 Why the Area Model Works
①x² is the big square, (a+b)x are two rectangles, ab is the small one
②Sum of all four = the expansion
③This is the foundation of multiplication formulas
④In this sketch a is 3

Polynomial Division — Synthetic

When dividing by (x − a), synthetic division gives the quotient and remainder quickly.

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🔑 How Synthetic Division Works
①Write a on the left when dividing by (x − a)
②Drop the leading coefficient
③Multiply that by a, add to the next coefficient
④The last entry is the remainder

Division Identity

If you only memorize the order of filling the table from the top, you lose why the last cell is read as remainder. When the divisor is linear, what is left must be a constant, so that cell closes the identity rather than becoming another term of the quotient. Skip the degree condition and you glue that number onto the end of the quotient. Seeing first that integer division already keeps quotient and remainder in separate seats makes clear which cell closes the equation, before any memorized order.

Polynomial Division Identity
f(x) = (x − a) · Q(x) + R
dividend = divisor × quotient + remainder
Identity Property
(degree n) ÷ (degree 1) → quotient degree n−1, remainder constant
Each division reduces the degree by 1
📐 Compare with Integer Division
①17 ÷ 5 = 3 … 2 → 17 = 5 × 3 + 2
②Polynomials follow the same shape: f(x) = divisor × quotient + remainder
③Remainder degree < divisor degree (always!)
④Degree of dividend = degree of quotient + degree of divisor

Multiplication Formulas

Perfect Square
(a ± b)² = a² ± 2ab + b²
Expansion of a square
Sum × Difference
(a + b)(a − b) = a² − b²
Difference of squares
Cube Expansion
(a + b)³ = a³ + 3a²b + 3ab² + b³
n = 3 case of the binomial theorem

Work It Out

When you expand a square, or a symmetric pair given only a sum and a product, first match the left side of a formula to the shape you were given. Before you replace letters with numbers, mark which term sits on which tile of the area picture; that cuts dropped coefficients and flipped signs. Before you write the answer, count that the number of terms you wrote matches the number of terms in the formula. A cube is the same seat with one more layer.

Example 1
Expand (x + 3)².
1
Use the perfect-square formula (a + b)² = a² + 2ab + b².
(x + 3)² = x² + 2·x·3 + 3²
2
Simplify.
x² + 6x + 9
x² + 6x + 9
Memorizing the product formulas speeds up expansion.
Example 2
If x + y = 5 and xy = 3, find x² + y².
1
Use the identity x² + y² = (x + y)² − 2xy.
x² + y² = (x + y)² − 2xy
2
Substitute the values.
= 5² − 2·3 = 25 − 6 = 19
x² + y² = 19
Given the sum and product, get a symmetric expression via the identities.

Wrap-up

The habit of reading the last cell as remainder is what the next page uses when it plugs a number into x and reads that cell at once. Turning a product formula backwards to find a factor sits on that same identity. The 1 at the left of the table is the root of (x-1), so putting a value in that seat is where the next theorem starts. Because the tiles and the table already share the letter x, you carry those letters forward instead of renaming them.

Core Division Identity
f(x) = (divisor) × Q(x) + R
Backbone of polynomial division
Grade-10 school exam type
If x + y = 4 and xy = 2, what is x³ + y³?
28
34
40
46
52
③ 40
1
Use the identity x³ + y³ = (x + y)³ − 3xy(x + y).
x³ + y³ = (x + y)³ − 3xy(x + y)
2
Substitute the values.
= 4³ − 3·2·4 = 64 − 24 = 40
🎯 Exam Points
①Multiplication formulas ↔ factoring — master both directions
②Synthetic division feeds directly into the Remainder Theorem
③Plug a number into the identity to find the remainder
④Cube expansion extends to the binomial theorem
⑤Degree: dividend = quotient + divisor
Next →
Remainder & Factor Theorem
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