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Grade 12 / High 3 (age 17-18)

Vector Operations

Vector Operations

A vector is an arrow carrying both a direction and a size. Join two arrows and the diagonal of the parallelogram is exactly their sum, while multiplying an arrow by a number (a scalar) keeps its direction but stretches, shrinks, or flips it. The neat part is that all of this comes down to adding and multiplying the x- and y-components separately. Drag the components of a and b with the sliders to watch the sum vector appear, then change k to see the arrow stretch and flip.

Vector Addition
3
2
1
3
👀 Intuition for Vector Addition
①Red arrow a and blue arrow b start from origin O
②Form a parallelogram from the two arrowheads
③The diagonal is the sum vector a+b (gold)
④Just add components: (a_x+b_x, a_y+b_y)
Scalar Multiplication
1.5
↔️ What is Scalar Multiplication?
①k > 1: extends in the same direction
②0 < k < 1: shrinks in the same direction
③k < 0: flips to the opposite direction
④k = 0: becomes the zero vector
Vector Operation Laws
Vector Addition (Components)
a + b = (ax + bx, ay + by)
Add corresponding components
Scalar Multiplication (Components)
ka = (kax, kay)
Multiply each component by k
📐 Operation Laws
①Commutative: a + b = b + a
②Associative: (a + b) + c = a + (b + c)
③Distributive: k(a + b) = ka + kb
④Distributive: (k + m)a = ka + ma
Position Vectors and Internal/External Division
Position Vector of Internal Division
p = na + mbm + n
Point P that divides segment AB in ratio m:n
Position Vector of Midpoint
p = a + b2
Special case m = n = 1
🎯 Mnemonic for Division Formula
①m:n internal division → cross the opposite ratios
②Denominator is always m+n
③Midpoint is simply the average
④External division: denominator becomes m−n (mind the sign)
Work It Out
Example 1
Given a=(2, 3) and b=(−1, 4), find a+b and 2a−b.
1
Addition is done component by component.
a + b = (2+(−1), 3+4) = (1, 7)
2
Scalar multiplication then subtraction is also component-wise.
2a − b = (4−(−1), 6−4) = (5, 2)
a+b=(1, 7), 2a−b=(5, 2)
Vector operations work on the x-components and y-components separately.
Example 2
Given a=(3, −4), find the magnitude |a| and the unit vector in the direction of a.
1
The magnitude comes from the Pythagorean theorem.
| a | = √(3² + (−4)²) = √25 = 5
2
The unit vector is a divided by its own magnitude.
a / | a | = (35, −45)
|a|=5, unit vector=(3/5, −4/5)
A unit vector keeps the same direction but has magnitude 1.
Summary
Vector Magnitude
| a | = √(ax² + ay²)
Magnitude (length) by Pythagorean theorem
2023 KICE mock exam Math (Geometry) type, adapted
For two vectors a=(1, 2) and b=(3, k), if a + b = (4, 5), what is the value of k?
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2
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5
③ 3
1
Addition is component-wise, so compare the y-components.
2
y-component: 2+k=5.
2 + k = 5 ⇒ k = 3
🎯 Exam Points
①Vector addition: add components
②Scalar multiplication changes direction (sign) and magnitude (absolute value)
③Parallel condition: a = kb (some nonzero scalar k exists)
④Memorize the cross order in the division formula
⑤Unit vector: a / |a| (magnitude 1)
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Inner Product
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