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Grade 12 / High 3 (age 17-18)

Limit of a Sequence

Limit of a Sequence

A sequence is an endless line of numbered values, one for each n. The real question is whether those values settle toward a single destination as n grows larger and larger, and that destination is what we call the limit. If the terms crowd arbitrarily close to one number we say the sequence converges; if they scatter or bounce forever, it diverges. Drag the term-count slider to watch the dots close in on L = 1, then switch between sequences to compare convergence against divergence side by side.

Where the Sequence Heads
5
👀 See It
Each gold dot is a term of the sequence. As n grows, dots approach the red dashed line (L = 1). That's 'convergence'.
ε-N Definition
📏 Meaning of the ε-Band
①Larger n shrinks the gold band (ε-band)
②No matter how tiny ε is, all terms past some N stay inside
③That's the rigorous definition of convergence
ε-N Definition
∀ε > 0, ∃N : n ≥ N ⇒ |an − L| < ε
For every ε > 0 there exists N such that n ≥ N ⇒ |aₙ − L| < ε
Convergent vs Divergent
0
🔍 Three Patterns
①Mode 0: 1 + 1/n → 1 (clusters together)
②Mode 1: (−1)ⁿ(1 + 1/n) — oscillates, diverges
③Mode 2: n/(n+1) → 1 (approaches from below)
Limit Laws
Arithmetic of Limits
lim(an ± bn) = α ± β, lim(an · bn) = α · β
Sum/diff/product of limits when both sequences converge
Quotient
lim anbn = αβ (β ≠ 0)
Quotient of limits when β ≠ 0
Squeeze Theorem
an ≤ cn ≤ bn, lim an = lim bn = L ⇒ lim cn = L
If two sequences squeeze a third to the same limit, that third converges to it
Worked Examples
Example 1
Find limn→∞ 2n+3n-1.
1
Divide numerator and denominator by n.
2n+3n-1 = 2 + 3/n1 - 1/n
2
As n → ∞, 3/n → 0 and 1/n → 0.
2 + 01 - 0 = 2
2
For limits of rational expressions, dividing by the highest power in the denominator is the standard move.
Example 2
Find limn→∞ sin nn.
1
Since −1 ≤ sin n ≤ 1, divide all sides by the positive number n.
-1nsin nn1n
2
Both outer limits are 0, so by the squeeze theorem the middle is 0.
limn→∞ (-1/n) = limn→∞ 1n = 0
0
For bounded sequences like sin or cos, squeeze with ±1/n and apply the squeeze theorem.
Wrap-up
Key Limits
limn→∞ 1np = 0 (p > 0), limn→∞ rn = 0 (|r| < 1)
1/np → 0; rn → 0 when |r| < 1
CSAT-style
What is limn→∞ (√(n2+3n) − n)?
1
32
2
3
∞ (diverges)
32
1
This is an ∞ − ∞ form with a root, so multiply by the conjugate to rationalize.
√(n2+3n) − n = 3n√(n2+3n) + n
2
Divide numerator and denominator by n; the denominator tends to 2.
3√(1 + 3/n) + 132
🎯 Exam Points
①Definition: master the ε-N flow
②Use limit laws once each part converges
③Diverging sequences (oscillating) have no limit
④Squeeze theorem when two limits agree
⑤Memorize 1/n^p → 0 and r^n → 0 (|r| < 1)
Next →
Limit of a Geometric Sequence
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