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Grade 12 / High 3 (age 17-18)

Equations & Inequalities

Equations & Inequalities

Real Roots Are Graph Intersections
0
👀 See It
①The real roots of f(x)=k are the intersections of y=f(x) and y=k
②Raising or lowering k switches the count between 1 and 3
③The boundaries are the moments it passes the local max and min
Counting Roots of a Cubic
Judge by the sign of extrema
(local max) × (local min) < 0 ⇒ three distinct real roots
If the product is 0, a double root (2); if greater than 0, just 1
Separate Into the Form f(x)=k
Constant separation
number of roots of f(x)=k = intersections of y=f(x) with y=k
Seen as a moving horizontal line y=k, the extrema become the boundaries
Solve It Directly
Example 1
Find the number of distinct real roots of x³−3x+1=0.
1
f(x)=x³−3x+1, and f'(x)=3x²−3=0 gives x=±1.
2
Local max f(−1)=3>0, local min f(1)=−1<0 — opposite signs.
(local max)(local min) < 0 ⇒ 3 real roots
3
For a cubic, the signs of the local max and min give the root count immediately.
Example 2
Show that x³−3x+2 ≥ 0 for all x ≥ 0.
1
g(x)=x³−3x+2, and g'(x)=3x²−3=0 gives x=1 within x≥0.
2
On x≥0 the minimum is g(1)=1−3+2=0 ≥ 0.
minx≥0 g(x) = g(1) = 0 ⇒ g(x) ≥ 0
minimum 0 ≥ 0, so it holds
Proving an inequality means showing the minimum of (LHS−RHS) is at least 0.
Wrap-up
Core strategy
root count = graph intersections, inequality = sign of the minimum
Equations via the sign of extrema, inequalities via the minimum — both solved by differentiation
2022 provincial mock exam Math type, adapted
For which range of k does x³−3x = k have three distinct real roots?
k < −2
−2 < k < 2
k > 2
k = ±2
all real numbers
② −2 < k < 2
1
f(x)=x³−3x, and f'(x)=3x²−3=0 gives local max f(−1)=2, local min f(1)=−2.
2
Three roots require the line y=k to lie between the local min and max.
−2 < k < 2
🎯 Exam Points
①Reduce equation roots to graph intersections
②A cubic’s root count comes from the sign of (max)(min)
③For f(x)=k, separate the constant and move a horizontal line
④For inequalities, show the minimum of the difference ≥ 0
⑤With a restricted domain, use the minimum on that interval
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