Three-phase connections: Y and Δ
Add the three EMFs down to zero
Three phasors spin together at the same speed. Change the phase spacing until their sum (the red arrow) vanishes.
Y connection · joined at one point
Tie one end of all three coils (a, b, c) to a single point. That common point is the neutral N. The other three ends run outward as the lines. When balanced, the currents arriving at the neutral also sum to zero, so the potential holds steady even with no neutral wire.
Δ connection · closed into a loop
Connect the end of each coil to the start of the next: a-end to b-start, b-end to c-start, c-end to a-start. The three coils form a closed triangle loop. There is no neutral. The instant the loop closes, the three EMFs add in series around it, and only if that sum is zero does no circulating current flow.
Why the sum is zero
Picture the three EMFs as arrows on a plane: equal length, fanned out 120 degrees apart. Add the horizontal components together and the vertical components together, and each side cancels exactly. This is why the neutral-wire current in Y is zero, and why the delta loop can be closed safely.
Back to the first screen
The red sum arrow vanished exactly when the spacing was 120 degrees. Gather that balanced set at one point and you get Y; close it into a loop and you get the delta (Δ) connection. The two are not different sources but two ways of joining the same three EMFs, and the single fact that they sum to zero guarantees both the steady Y neutral and the safety of the delta loop at once.
With the same balanced set in hand, the next unit (PW-A2) shows how the connection appears in voltage and current. In Y the line voltage is √3 times the phase voltage; in delta the line current is √3 times the phase current. That √3 comes straight from the difference of two of the phasors you added here.