seegongsik
Saved words
CR · Frequency response

Cutoff Frequency and the First-Order Low-Pass

The same RC circuit passes a signal differently depending on its frequency. Learn to read where it lets signals through and where it starts blocking them — the boundary called the cutoff frequency.

Lows pass, highs are blocked

Sweep the frequency from low to high. At first the signal comes out almost untouched, then it shrinks. Find the cutoff frequency ω_c where the output drops to 1/√2 of the input, that is −3 dB.

Frequency ω / ω_cω/ω_c = 0.20
Pass-through gain
|H| = 0.981 · -0.2 dB
Far from cutoff

The capacitor makes a frequency-dependent divider

Put a resistor and a capacitor in series and take the output across the capacitor, and the two form a voltage divider. But the capacitor’s impedance 1/ωC falls as frequency rises. At low frequency the capacitor takes almost all the voltage, so the output nearly equals the input; at high frequency the capacitor’s share shrinks and the output collapses.

The cutoff frequency ω_c = 1/RC

The boundary is the frequency where the resistor’s and capacitor’s impedances are equal. That is ω_c = 1/RC, and because the two equal impedances are at a right angle, the output drops to 1/√2 ≈ 0.707 of the input. In power that is one half, so it is called the −3 dB point. In phase, the output lags the input by exactly 45 degrees.

Above cutoff it rolls off at a fixed slope

Above the cutoff, each tenfold rise in frequency cuts the gain to one tenth — that is −20 dB per decade. This fixed slope is the signature of a first-order filter. On log axes the flat pass-band line and the −20 dB/decade falling line meet at a corner, and that corner is the cutoff frequency.

Observe|H| = 1/√(1+(ω/ωc)²)
Gain falls as frequency rises.
Chooseωc = ?
Where the two impedances are equal.
Fill inω = ωc → |H| = ?
Equal at a right angle gives 1/√2.
On your ownω = ωc → φ = ?
At cutoff the output lags by 45 degrees.

Back to the first screen

As you raised the frequency, the pass-through gain began flat, then bent down near the cutoff, and at exactly ω_c = 1/RC the output became 0.707 of the input, −3 dB. Above that it fell a steady −20 dB per tenfold. That the same circuit passes or blocks depending on which frequency you send is summed up by a single cutoff frequency.

A first-order low-pass is an RC divider with gain |H| = 1/√(1+(ω/ωc)²). At the cutoff frequency ωc = 1/RC the output drops to 1/√2 (−3 dB) of the input and the phase becomes −45 degrees. Above it the gain falls at a steady −20 dB/decade. It passes low frequencies and blocks high ones.