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CR · Frequency response

Cutoff and the First-Order High-Pass

The very same resistor and capacitor as a low-pass, but changing only where you take the output flips its behavior. Learn to read the cutoff of a high-pass, which blocks low frequencies and passes high ones.

Highs pass, lows are blocked

Sweep the frequency from low to high. At first it is almost blocked, then it passes more and more. Find the cutoff frequency ω_c where the output rises to 1/√2 of the input, that is −3 dB.

Frequency ω / ω_cω/ω_c = 0.20
Pass-through gain
|H| = 0.196 · -14.2 dB
Far from cutoff

This time the output is across the resistor

A low-pass took its output across the capacitor. A high-pass looks across the resistor of the same series RC. At low frequency the capacitor’s impedance 1/ωC is huge, so it takes almost all the voltage and the resistor gets almost none — low frequencies are blocked. As the frequency rises the capacitor’s share shrinks and the resistor receives the voltage, so high frequencies pass.

The cutoff frequency ω_c = 1/RC

Just as in the low-pass, the boundary is the frequency where the resistor’s and capacitor’s impedances are equal. That is ω_c = 1/RC, and the output drops to 1/√2 ≈ 0.707 of the input — −3 dB. Only the phase has the opposite sign: in a high-pass the output leads the input by 45 degrees, approaching +90 degrees as you go below cutoff.

Below cutoff it rises at a fixed slope

Above the cutoff the gain is flat at nearly one. Below it, each tenfold drop in frequency cuts the gain by −20 dB. On log axes the flat line above cutoff and the −20 dB/decade falling line below (a +20 dB/decade rise as you sweep up) meet at a corner, the cutoff. A high-pass is used to block the DC component and pass only the changing part of a signal — as a differentiator or a coupling capacitor.

Observe|H| = (ω/ωc) / √(1+(ω/ωc)²)
Gain rises as frequency rises.
Chooseωc = ?
Where the two impedances are equal.
Fill inω = ωc → |H| = ?
It drops to 1/√2 at cutoff.
On your ownω = ωc → φ = ?
At cutoff the output leads by 45 degrees.

Back to the first screen

As you raised the frequency, the pass-through gain began near zero, bent upward near the cutoff, and at exactly ω_c = 1/RC the output became 0.707 of the input, −3 dB. Above that it leveled off toward one. The same parts as a low-pass, with the single difference of taking the output across the resistor, flipped which frequencies pass clean over.

A first-order high-pass takes the output across the resistor of a series RC, with gain |H| = (ω/ωc)/√(1+(ω/ωc)²). At the cutoff frequency ωc = 1/RC the output is 1/√2 (−3 dB) of the input and the phase is +45 degrees. Above it the gain is flat at one; below it falls at −20 dB/decade. It blocks DC and low frequencies and passes high ones.