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CR · Frequency response

Cutoff and the First-Order High-Pass

It uses exactly the same resistor and capacitor as the low-pass filter, yet changing only where the output is taken makes it behave the opposite way. This unit shows how to read the cutoff frequency of a high-pass filter, which blocks low frequencies and passes high ones.

Highs pass, lows are blocked

The graph's horizontal axis is frequency on a logarithmic scale, and the vertical axis is the gain, the ratio of output size to input size. Raise the frequency from low to high: at first the signal is almost blocked, then it gradually gets through; find the cutoff frequency where the gain climbs to 1/√2, that is, −3dB. The lower tick on the vertical axis marks exactly that height.

Frequency ω / ω_cω/ω_c = 0.20
Pass-through gain
|H| = 0.196 · -14.2 dB
Far from cutoff

This time the output is across the resistor

The low-pass filter took its output across the capacitor, but the high-pass filter looks across the resistor of the same series RC. At low frequencies the capacitor's impedance, 1/ωC, is very large, so it takes almost all the voltage and hardly any appears across the resistor. That is why low frequencies are blocked. As the frequency rises the capacitor's share shrinks and the resistor picks up the voltage, so high frequencies get through.

The cutoff frequency ω_c = 1/RC

Just as with the low-pass filter, the boundary is the frequency at which the resistance and the size of the capacitor's impedance become equal. That point is ω_c = 1/RC, and the output becomes 1/√2 ≈ 0.707 times the input, that is, −3dB. The sign of the phase is reversed, however: in the high-pass filter the output leads the input by 45 degrees, and the phase approaches +90 degrees as you go further below the cutoff.

Below cutoff it rises at a fixed slope

Above the cutoff the gain is nearly 1 and flat. Below the cutoff, every time the frequency drops tenfold the gain falls to 1/10, that is, by −20dB. This plot draws the gain itself on the vertical axis, but in a Bode plot drawn in dB, the corner where the flat line above the cutoff meets the line below it sloping at −20dB/decade (or +20dB/decade read going upward) is the cutoff frequency. High-pass filters are used to block the DC component and pass only the changes in a signal, as in differentiators and coupling capacitors.

Observe|H| = (ω/ωc) / √(1+(ω/ωc)²)
The higher the frequency, the larger the gain.
Chooseωc = ?
It is where the two impedances become equal in size.
Fill inω = ωc → |H| = ?
At the cutoff the gain is 1/√2.
On your ownω = ωc → φ = ?
At cutoff the output leads by 45 degrees.

Back to the first screen

As you raised the frequency, the gain started near 0, bent upward near the cutoff, and at exactly ω_c = 1/RC the output was 0.707 times the input, −3dB. Above that it flattened out toward 1. The very same parts as the low-pass filter, with the single difference of taking the output across the resistor, turned the passed frequencies exactly around.

A 1st-order high-pass filter takes the output across the resistor of a series RC, with gain |H| = (ω/ωc)/√(1+(ω/ωc)²). At the cutoff frequency ωc = 1/RC the output is 1/√2 (−3dB) of the input and the phase is +45 degrees. Above the cutoff it is flat (1), and below it falls at −20dB/decade. It blocks DC and low frequencies and passes high frequencies.