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Grade 10-11 (age 15-17)

Molar Concentration

Molar Concentration

Same Amount, Different Volume, Different Strength
2 L
👀 See It
①Even with the same amount of solute (moles), a larger solution volume is more dilute
②Molar concentration is the moles of solute per 1 L of solution
③Dissolving the same moles in a larger volume lowers the concentration
Definition of Molar Concentration
Molar concentration
M = nV
Moles of solute n (mol) divided by solution volume V (L) — units mol/L
Moles–concentration–volume
n = M V
Knowing concentration and volume gives the dissolved moles at once
Dilution — Making It Weaker
Dilution formula
M V = M′ V′
Concentration × volume before = concentration × volume after
💧 The Moles of Solute Stay the Same
①Dilution adds water, increasing only the volume
②The moles of solute do not change
③Hence M V = M′ V′ (equal moles before and after)
Compute It Directly
Example 1
Dissolve 0.5 mol of NaOH in water to a total volume of 2 L. Find the molar concentration.
1
Put n=0.5, V=2 into M = n/V.
M = 0.52
2
Compute.
M = 0.25 mol/L
0.25 mol/L
Volume must be in L — for mL, divide by 1000 to get L.
Example 2
Adding water to 100 mL of a 2 M solution to make 500 mL total — what is the concentration?
1
It is dilution, so use M V = M′ V′.
2 × 100 = M′ × 500
2
Solve for M′.
M′ = 200500 = 0.4 M
0.4 M
In dilution, if the volume unit is the same on both sides, mL works directly.
Wrap-up
Key result
M = nV, n = M V, M V = M′ V′
Concentration = moles/volume, moles = conc × volume, dilution preserves the product
2021 CSAT Science (Chemistry Ⅰ) type, adapted
How many moles of sulfuric acid are in 200 mL of a 1.5 M solution?
0.1 mol
0.2 mol
0.3 mol
0.45 mol
3 mol
③ 0.3 mol
1
n = M V; convert volume to L (200 mL = 0.2 L).
n = 1.5 × 0.2
2
Compute.
n = 0.3 mol
🎯 Exam Points
①molar concentration M = n/V (V in L)
②n = MV converts to moles
③dilution is M V = M′ V′
④convert mL to L by dividing by 1000
⑤it is the solution (total) volume, not the solvent (water) volume
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